Question

A vessel is in the form of an inverted cone. Its height is 8 cm and the
radius of its top, which is open, is 5 cm. It is filled with water up to the
brim. When lead shots, each of which is a sphere of radius 0.5 cm are
dropped in to the vessel, one – fourth of the water flows out. Find the
number of lead shots dropped in the vessel.

Answer 1

Height of cone  h = 8 cm

Radius r = 5 cm

Volume of cone = $\boxed{ \frac{1}{3} \times \pi \times {r}^{2} \times h}$

Volume = $\frac{1}{3} \times \frac{22}{7} \times {5}^{2} \times 8$

Volume = 209.52 cm sqaure

Water overflowed = volume of lead shot

$\frac{1}{4} \times 209.52=52.38$

volume of lead shot =$\frac{4}{3} \times \pi \times {r}^{3}$

volume of lead shot =$\frac{4}{3} \times \frac{22}{7} \times {0.5}^{3}$

volume of lead shot =0.523 cm cube

therefore , no.of lead shot will be=$\boxed {\frac{Volume of lead shot droped}{volume of one lead shot}}$

=$\frac{52.38}{0.523}$

=100 lead shots

Answer 2

Heya...

Here's your answer.........

Radius of cone = 5 cm

Height of cone = 8cm

Volume of cone = 1/3 πr2h

= 1/3 ×22/7 5×5×8

= 1×22×5×5×8/3×7

=4400/21 cm3

1/4 volume of cone =1/4 × 4400/21

=1100/21 cm3

Volume of sphere = 4/3πr3

=4×22×0.5×0.5×0.5/3×7

= 11 /21 cm3

Number of sphere = 1100/21 ×21/11

=100

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✨✨✨✨BY BeWaFa ✨✨✨

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Thanks...!!!

XD

Sorry baby 'wink'