Question

A vessel is in the form of an inverted cone. Its
height is 8 cm and the radius of its top, which is
open, is 5 cm. It is filled with water up to the brim.
When lead shots, each of which is a sphere of radius
0.5 cm are dropped into the vessel, one-fourth of
the water flows out. Find the number of lead shots
dropped in the vessel.
​

Answer 1

I/4th of the vol. of the cone =

I/12xπx25x8

vol. of a leadshot-4/3πx.5x.5x.5

No. of.leadshots dropped =

50/ 0.50 = 100

Ans: l00 shots

Answer 2

Answer: 100 shots

Step-by-step explanation:

The Vessel’s, Height (h) = 8 cm, Radius (r) = 5cm  

⇒    volume of vessel=1/3 πr^2 h=1/3×22/7×5^2×8

⇒   =4400/21  

As, when lead shots are dropped into the vessel, one-fourth of the water flows out, therefore

⇒   volume of water flows out

     =1/4 × volume of vessel  

⇒  =1/4 × 4400/21 = 1100/21

⇒ volume of each lead shot = 4/3 π r^3

⇒   = 4/3×22/7× [/tex]0.5^3=11/21

⇒    volume of water flows out = number of lead shot  × volume of each lead shot

⇒  1100/21 = n×11/21

⇒  n = 100