Question

a vessel of 5 l capacity maintained at 27°C was filled with 16 g of O2 gas . calculate the pressure of the gas in the atmosphere in the container

Answer 1

volume of gas=volume of cylinder
V=5 lite
T=27°C=27+273=300K
given mass(m)=16g
molar mass of O2=32g
n=mM=16/32=1/2mol
pressure(P)=?
applying ideal gas equation
PV=nRT
P=nRT/v
=0.5×0.0821×300/5
=2.46 atm

Answer 2

$\huge{Hello Friend}$

The answer of u r question is..✌️✌️

Ans:❤️❤️❤️❤️❤️❤️❤️❤️

Volume of gass=volume of cylinder

V = 5 liters

T = 27°c

=27+273

= 300K

Mass = 16g

Molar mass of o2 = 32g

n=m/M

=16/36

=1/2 Mol

Pressure = ?

Formula

PV= nRT

P=nRT/V

=0.5×0.0821×300/5

=2.46 atoms


Thank you..⭐️⭐️