Question

A vibrating tuning fork can produce a note of wavelength
0.95 m and has a time period of 2.5x10 3 sec. calculate the wave
velocity. please answer fast​

Answer 1

Answer:

we know , velocity (V) = lambda × F

lambda or wavelength = 0.95m or 9.5×10^(-1)

T = 2.5×10³

therefore, F = 1/(2.5×10³)

so, V = [9.5×10^(-1)]/(2.5×10³)

= (9.5/2.5) × [10^(-1)/10³]

= 3.8×10^(-4)

= 3.8/10000

= 0.00038m/s

hope it helped :)