Math, asked by dd24, 11 months ago

A village had a population of 25,000 three years ago. During the first year, second and third year, the population increased at the rate of 5% ,6% and 8% respectively. What is the present population of the village?pls answer question asap.


dd24: pls

Answers

Answered by TooFree
58

Answer:

30051


Step-by-step explanation:

Initial population = 25,000


Find the population after 1st year:

Increase = 5% of 25000

Increase = 0.05 x 25000 = 1250

Population = 25000 + 1250 = 26,250


Find the population after 2nd year:

Increase = 6% of 26, 250

Increase = 0.06 x 26250 = 1575

Population = 26250 + 1575 = 27825


Find the population after 3rd year (Present population):

Increase = 8% of 27825

increase = 0.08 x 27825 = 2260

Population = 27825 + 2260 = 30051


Answer: The present population is 30051


dd24: thanks.
TooFree: Welcome :)
Zeeshu100: Thanks
Answered by stackhouse192
23

First Year


Population increased by 5%


5% of 25000


= 5/100 × 25000


= 1250


Population after 1 year = 25000 + 1250


= 26250


Second Year


Population increased by 6%


6% of 26250


= 6/100 × 26250


=1575


Population after 2 years = 26250 + 1575


= 27825


Third Year


Population increased by 8%


8% of 27825


= 8/100 × 27825


=2226


Population after 3 years = 27825 + 2226


Answer = 30051


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