Question

A village having a population of 4000, requires 150 litres of water per head per day. It has a tank measuring 20m x 15m x 6m. For many days will the water of this tank last?

Answer 1

Answer:

3 days

Step-by-step explanation:

Volume of tank =20×15×6=1800m^3

1m^3=1000litres

1800m^3=18,00,000litres

water required in the village per day=4000×150=6,00,000litres

no. of days water in tank will last=18,00,000/6,00,000=3days

Answer 2

✯✯ QUESTION ✯✯

A village having a population of 4000, requires 150 litres of water per head per day. It has a tank measuring 20m x 15m x 6m. For many days will the water of this tank last?

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✰✰ ANSWER ✰✰

$\implies\tt{Total\:Population=4000}$

$\implies\tt{In\:one\:Day\:one\:Person\:Use=150\:litre}$

$\implies\tt{In\:one\:Day\:4000\:Person\:Use=150\times{4000}}$

$\implies\tt\bold{600000\:litre}$

$\implies\tt{Length\:of\:Tank=20m}$

$\implies\tt{Breadth\:of\:Tank=15m}$

$\implies\tt{Height\:of\:Tank=6m}$

➥Using Formula : -

$\implies\tt{\small{\boxed{\bold{\bold{\red{\sf{Volume\:of\:Cuboid=l\times{b}\times{h}}}}}}}}$

➥Putting Values : -

$\implies\tt{20\times{15}\times{6}}$

$\implies\tt\bold{1800{m}^{3}}$

➥Now ,

$\implies\tt{1{m}^{3}=1000\:l}$

$\implies\tt{1800\times{1000}}$

$\implies\tt\bold{1800000\:l}$

$\implies\tt{No\:of\:Days=\cancel\dfrac{1800000}{600000}}$

$\implies\tt\boxed{3\:days}$