A village supplied water through pipe lines every third day.The water was first supplied on 1st January.the last was supplied on 31st January?10000kl of water was supplied on 1st January. Subsequently,the quota of water was increased by 500 liters each time. How much water was supplied during month of January?
Answers
Water supplied during month of January = 137500 litre
Step-by-step explanation:
Water Supplied every 3rd days
1st Day 4th Day , 7th Day .....................................28th Day , 31st Day
31 = 1 + (n-1)*3
=> n- 1 = 10
=> n = 11 Days
Water supplied for 11 Days
10000 kl on first day
500 litre = 0.5 kl increased each time
a = 10000
d = 0.5
n = 11
Total water Supplied = (n/2)(2a + (n-1)d)
= ( 11/2)(20000 + 10 * 0.5)
= (11/2)(20005)
= 1,10,027.5 kl
if 10000 is also in litre
a = 10000
d = 500
n = 11
Total water Supplied = (n/2)(2a + (n-1)d)
= ( 11/2)(20000 + 10 * 500)
= 11 * 25000 /2
= 137500 litre
Water supplied during month of January = 137500 litre
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Answer:The total quantity of water supplied is 110027.5 kl
Step-by-step explanation:
The water is supplied every third day starting from 1st January till 31st January
1,4,7,....,31 is a sequence with first term a=1 and the common difference d=3
It is an A.P.
Let the water was supplied for n times during January
tn = 31
tn = a+(n-1) d ....(Formula)
31 = 1+(n-1)×3 .....(Substituting the values)
31 = 1+3n-3
3n = 31-1-3
3n = 33
n = 11
The water was supplied 11 times during January.
Now , we have to find the total quantity of water supplied
For this, a=10000kl , d=500l =0.5 kl , n=11
Sn =n/2 [2a+(n-1)d] ....formula
= 11/2 [2×10000+(11-1)×0.5]
= 11/2 [20000+10×0.5]
= 11/2 [20005]
Sn = 110027.5