Question

A villager went to a hotel in a town with his big family . They consumed 23 idlies,18 poories,7 dosas,19 vadas.the bill was rs. 108. Next day they consumed 34 idlies, 8 vadas,22 poories,7 dosas ,the bill became rs.114.If one idli costs same as vada.What is the cost of one poorie.

Answer 1

The cost of one poorie is Rs. 1.50

Step-by-step explanation:

A villager went to a hotel in a town with his big family.

Let P for Poorie, I for Idli, V for Vada, D for Dosa.

He consumed 23 idlies, 18 poories, 7 dosas, 19 vadas and the bill was Rs. 108.

23I + 18P + 7D + 19V = 108...............(i)

He consumed 34 idlies, 8 vadas, 22 poories, 7 dosas next day and bill was Rs. 114.

34I + 8V + 22P + 7D = 114..............(ii)

One idli costs same as vada.

So, I = V

Now equation(i) and (ii) becomes,

23V + 18P + 7D + 19V = 108

=> 42V + 18P + 7D = 108................(iii)

34V + 8V + 22P + 7D = 114

=> 42V + 22P + 7D = 114...................(iv)

Subtract equation(iii) from equation(iv),

42V + 22P + 7D - (42V + 18P + 7D) = 114 - 108

=> 42V + 22P + 7D - 42V - 18P - 7D = 6

=> 4P = 6

=> P = $\frac{6}{4} = Rs. 1.50$

Hence, the cost of one poorie is Rs. 1.50

Answer 2

Let P for Poorie, I for Idli, V for Vada, D for Dosa.

He consumed 23 idlies, 18 poories, 7 dosas, 19 vadas and the bill was Rs. 108.

23I + 18P + 7D + 19V = 108...............(i)

He consumed 34 idlies, 8 vadas, 22 poories, 7 dosas next day and bill was Rs. 114.

34I + 8V + 22P + 7D = 114..............(ii)

One idli costs same as vada.

So, I = V

Now equation(i) and (ii) becomes,

23V + 18P + 7D + 19V = 108

=> 42V + 18P + 7D = 108................(iii)

34V + 8V + 22P + 7D = 114

=> 42V + 22P + 7D = 114...................(iv)

Subtract equation(iii) from equation(iv),

42V + 22P + 7D - (42V + 18P + 7D) = 114 - 108

=> 42V + 22P + 7D - 42V - 18P - 7D = 6

=> 4P = 6

=> P = \frac{6}{4} = Rs. 1.50

4

6

=Rs.1.50

Hence, the cost of one poorie is Rs. 1.50