On a morning walk, three persons step off together and their steps measure 40 cm, 42 cm and 45 cm, respectively. What is the minimum distance each should walk so that each can cover the same distance in complete steps?NCERT Class XMathematics - Exemplar ProblemsChapter _Real Numbers
Answers
Answered by
1857
We have to find the LCM of 40 cm, 42 cm and 45 cm to get the required minimum
distance. Because we are asked the minimum distance
Now,
40 = 2 × 2 × 2 × 5,
42 = 2 × 3 × 7
45 = 3 × 3 × 5
∴ LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7 = 30 × 12 × 7 = 210 × 12 = 2520
Minimum distance each should walk 2520 cm. so that, each can cover the same distance in complete steps.
Now,
40 = 2 × 2 × 2 × 5,
42 = 2 × 3 × 7
45 = 3 × 3 × 5
∴ LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7 = 30 × 12 × 7 = 210 × 12 = 2520
Minimum distance each should walk 2520 cm. so that, each can cover the same distance in complete steps.
Answered by
565
To find the minimum distance we have to find the LCM of 40cm,42cm and 45cm
40 => 2 × 2 × 2 × 5 = 2³ × 5
42 = 2 × 3 × 7
45 = 3 × 3 × 5 × 7
=> 840 × 3 = 2520
So the distance to be covered by each = 2520cm
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