Question

a violin string emits sound with a frequency of 850 Hz . what is the distance between crest and neighbouring trough the passes through air? what is the period of vibration ? speed of sound = 340m/s

Answer 1

f = 850 Hz
v = 340 m/s

$\lambda= \frac{v}{f} = \frac{340}{850} =0.4m$

The distance between crest and trough is half of the wavelength. thus that will be 0.4/2 = 0.2m.

Period of vibration = $\frac{1}{f} = \frac{1}{850} = 0.00118s$

Answer 2

Given:

Frequency = 850 Hz.

Speed of sound = 340m/s.

To Find:

The distance between the crest and neighboring trough passes through the air.

Solution:

According to the formula,

Wavelength = Speed of sound / Frequency.

λ = ν / f.

λ = 340m/s / 850 Hz.

λ = 0.4m.

The distance between crest and trough is half of the wavelength and the period of vibration.

Therefore,

0.4 / 2 = 0.2m.

Period of vibration = 1 / f.

Period of vibration = 1 / 850.

Period of vibration = 0.00118sec.

Hence,  the distance between the crest and neighboring trough the passes through the air is 0.2m and period of vibration is 0.00118sec.