Question

A voltage source of 50 V is connected across a 10 KQ resistor. Find the current, the
conductance and the power.​

Answer 1

Answer:

v=50v

r=10ohm

I=?

p=?

by formula

V=RI

50=10×I

50/10= I

I=5 ampere

Power,P= VI

P=50×5

P=250 Watt

Answer 2

Answer:

Given:

Voltage V = 50 v, Resistance R = 10 KΩ = 10000 Ω

To find: Current, Conductance, and Power

Formula: According to the ohm’s law $\mathrm{V}=\mathrm{I} \times \mathrm{R}$

Calculation: From the formula

Current,  $\mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}}$

$\mathrm{I}=\frac{50}{10000}=5 \times 10^{-3} \mathrm{A}$.

Conductance, G$=\frac{I}{V}=\frac{5 \times 10^{-3}}{50}=10^{-4}$ Siemens.

Power, P $=\mathrm{I} \times \mathrm{V}=5 \times 10^{-3} \times 50=25 \times 10^{-2}$ Watts.

$\mathrm{V}=I \times \mathrm{R}$ according to ohms equation. The resistance given is 10 kilo ohm and it is converted into 10000 ohm. So, $I=\frac{V}{R}$ and we obtain the value by substituting the given value in the formula.

Conductance is the reciprocal of resistance. Hence the equation becomes

$\mathrm{V}=\frac{\text { Current }}{\text { Conductance }}$.