A voltmeter of 250 mV range having a resistance of 10 W is converted into an ammeter of 250 mA range. The value of necessary shunt is (nearly)
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Given: A voltmeter of 250 mV range having a resistance of 10 W is converted into an ammeter of 250 mA range.
To find: The value of necessary shunt ?
Solution:
- Now we have given the value of voltmeter of 250 mV.
- Resistance of 10 W.
- So shunt will be:
- S = V(g) / I - I(g)
- So here neglecting I(g), we get:
- S = V(g) / I
- S = 250 / 250 = 1 ohm
Answer:
So the shunt will be 1 ohm.
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