a wagon of mass 2000kg is seperated from a train travelling at 9km/h and the wagon comes to rest in 2 min.find resistance between the wheels of the wagon and the track...do the sum
Astrobolt:
Thats a good question, just not of biology
Do you want deceleration?
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Since the wagon was connected to the train before, it's initial velocity is the same as the train which 9km/hr
1 km/hr = (5/18) m/s
9km/hr = 2.5 m/s
It comes to rest, so it's final velocity is 0 m/s
It takes 2 min = 120 seconds to get to rest.
a = (0-2.5)/120
a = -0.02083 m/s^2
So the retarding force applied is
F = ma
F = (2000)×(-0.02083)
F = -41.667 N
So a force with a magnitude of {41.667 N} was applied in the direction opposite to the velocity of the wagon to bring it to rest in 2 min from an initial velocity of 9 km/hr by producing a deceleration of {0.02083 m/s^2} in it.
1 km/hr = (5/18) m/s
9km/hr = 2.5 m/s
It comes to rest, so it's final velocity is 0 m/s
It takes 2 min = 120 seconds to get to rest.
a = (0-2.5)/120
a = -0.02083 m/s^2
So the retarding force applied is
F = ma
F = (2000)×(-0.02083)
F = -41.667 N
So a force with a magnitude of {41.667 N} was applied in the direction opposite to the velocity of the wagon to bring it to rest in 2 min from an initial velocity of 9 km/hr by producing a deceleration of {0.02083 m/s^2} in it.
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