Question

a walks with some time t with velocity (v) due east and then he walks for same time t with velocity (v) due north.the average speed of man is​

Answer 1

Answer:

AVERAGE VELOCITY = √2 vt / ( t + t )

Explanation:

Average velocity = Displacement / Time

On solving east and north walk then you will get hypotenuse as displacement

DISTANCE = velocity × time

distance in east = vt

distance in north = vt

Then hypotenuse = √ (vt)^2 + (vt)^2

= √ v^2 t^2 + v^2 t^2

= √ ( 2 v square t square )

= √2 vt

DISPLACEMENT = √2 vt

TIME = t + t

AVERAGE VELOCITY = √2 vt / ( t + t )

Answer 2

Answer:

average Speed = Total Distance /Total Time

= V×t / t

= V

therefore Answer is V

Hope it helps you.

Have Good Day.