Question

A wall clock, which gains uniformly, is 1 minute slow at 11 am on Monday, and is 5 min 48 seconds fast at 1 pm on the following Monday. When did the clock display correct time? hmm​

Answer 1

Given :- A wall clock, which gains uniformly, is 1 minute slow at 11 am on Monday, and is 5 min 48 seconds fast at 1 pm on the following Monday. When did the clock display correct time ?

Solution :-

given that,

→ clock was 1 minute slow at = 11AM monday .

→ clock was 5 min. 48 seconds fast at = 1 PM monday.

So,

→ Time period = 1PM - 11AM = 2 hours.

we can say that , in 2 hours clock cover distance = 1 min slow to 5 min . 48 seconds(5 + 48/60 = 5 + 4/5 = 29/5 minutes) = 1 + (29/5) = (34/5) minutes. { As per Number line -1 to + (29/5) distance. }

Therefore,

→ clock cover distance of (34/5) minutes in = 2 hours.

→ clock cover distance of 1 minutes in = (2 * 5)/34 = (10/34) hours = (10/34) * 60 = (600/34) ≈ 17.64 minutes. ≈ 17 minutes 38 seconds.

we can say that, after 17.64 minutes clock cover 1 minute slow distance and comes at 0 (as per number line.)

Hence, Clock display correct time at 11:17:38 .