Question

A wall is 4 m high and 40 cm wide. It contains two windows of dimensions 2.5m×1mand a gate way of dimensions 2m×3m. If 2450 cubical slabs each of length 20 cm are required to construct the wall, find the length of the wall​

Answer 1

Answer:

15

Step-by-step explanation:

Length of wall be l

width = 40 cm x 0.4 m

Volume of wall = 4 x 0.4 x l

= 1.62 m^{3}m

3

Volume of windows = 2(2.5 m X 1m X 0.4 m)

= 2.4 m^{3}m

3

Volume of wall excluding window and gateway = 1.6 l - (2+2.4)m^{3}m

3

=(1.6 l - 4.4)m^{3}m

3

Volume of each slabs = (0.2)m^{3}m

3

= 0.008 m^{3}m

3

Number of slabs = \frac{Volume of walls }{Volume of each slabs}

Volumeofeachslabs

Volumeofwalls

\frac{2450}{1}

1

2450

= \frac{1.6l-4.4}{0.008}

0.008

1.6l−4.4

1.6l - 4.4 = 19.6

1.6 l = 19.6 +4.4

Answer 2

Answer:

15m

Step-by-step explanation:

Length of wall be l

width = 40 cm x 0.4 m

Volume of wall = 4 x 0.4 x l

= 1.62 m^{3}m

3

Volume of windows = 2(2.5 m X 1m X 0.4 m)

= 2.4 m^{3}m

3

Volume of wall excluding window and gateway = 1.6 l - (2+2.4)m^{3}m

3

=(1.6 l - 4.4)m^{3}m

3

Volume of each slabs = (0.2)m^{3}m

3

= 0.008 m^{3}m

3

Number of slabs = \frac{Volume of walls }{Volume of each slabs}

Volumeofeachslabs

Volumeofwalls

\frac{2450}{1}

1

2450

= \frac{1.6l-4.4}{0.008}

0.008

1.6l−4.4

1.6l - 4.4 = 19.6

1.6 l = 19.6 +4.4

l = \begin{gathered}\frac{24}{1.6\\}\end{gathered}

l = 15m