Math, asked by bandanachoudhary88, 2 months ago

a wall of dimensions 10m×10mhas door frame of dimension 3m×2and window 3/2m×1 m.
find the total labour cost for painting the wall if the labour charges for painting 1m sq of the wall is rs 4 per sq .m​

Answers

Answered by ITZANNIKET
3

SOLUTION :

Area of door = Length × Breadth

= L × B

= 3 m × 2 m

= 6 m^2

Area of wall including door = Length × Breadth

= L × B

= 10 m × 10 m

= 100 m^2

Area of wall excluding door = 100 - 6

= 94 m^2

Total labour charges for painting the wall is

= 2.50 × 94

= Rs. 235

Answered by Anonymous
1

Answer:

In mathematics, the Pythagorean theorem, also known as Pythagoras's theorem, is a fundamental relation in Euclidean geometry among the three sides of a right triangle. It states that the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares on the other two sides. This theorem can be written as an equation relating the lengths of the sides a, b and c, often called the "Pythagorean equation".

I hope this will be help you.

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