Math, asked by rohit71, 1 year ago

a wall of length 10m is to be built across an open ground the height of the wall is 5m thick ness of the wall is 42 cm if this wall is to be built with bricks of dimensions 42 cm×12cm×10xm,then how many bricks would be required?

Answers

Answered by AkashMandal
146
solution:-

length of the wall, l = 10 m = 100 cm

Breadth of the wall, b = 42 m = 4200 cm

Height of the wall, h = 5 m = 500 cm

Volume of the wall = l × b × h = 100 cm × 4200 cm × 500 cm = 21000000 cm3

Dimension of the brick = 42 cm × 12 cm × 10cm

∴ Volume of each brick = 42 cm × 12cm × 10 cm = 5040 cm3

Let the number of bricks required be n.

n × Volume of each brick = Volume of the wall
therefore, n= vol of the wall/ vol of each brick

n= 21000000cm³/5040cm³

n= 4166.67

Thus, the number of brick required is 4166.67

Anonymous: breadth = 42 cm not 24 metres
Anonymous: you have used entirely different values
Anonymous: Dimension of the brick = 24 cm × 12cm × 10 cm
Anonymous: Dimension of wall = 10 metres × 42 cm × 5 metres
AkashMandal: now
Anonymous: ??
Answered by Anonymous
70
Hi there !!
HI there !!

Wall dimensions :-

Length = l = 10 metres = 1000 cm

Breadth[thickness] = b = 42 cm

Height = h = 5 metre = 500 cm

Volume of the wall = lbh
= 1000 × 42 × 500
= 21000000 cm³

=============================

Brick dimensions :-

Length = l = 42 cm

Breadth = b = 12 cm

Height = h = 10 cm

Volume of 1 brick = lbh
= 42 × 12 × 10
= 5040 cm³

No: of bricks required = Volume of wall ÷ Volume of 1 brick

= 21000000 ÷ 5040
= 4166.67
= 4167 bricks [ approx.]
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