Question

A wall of the kitchen is 8 metre long and 6 metre wide which is to be fitted with tiles each of length 32 cm and breadth 25 cm. find the number of tiles required to cover the wall.

Answer 1

Answer:

600

Step-by-step explanation:

Area of wall = 8×6 = 48 m^2

Tile area = (32/100)×(25/100) = 8/100

Tiles = 48 / (8/100) = 600

Answer 2

600 tiles are required to cover the wall

Step-by-step explanation:

1 m = 100 cm

Length of wall = 8 m = 800 cm

Breadth of wall = 6 m = 600 cm

Area of wall =$Length \times Breadth = 800 \times 600 = 480000 cm^2$

Length of tile = 32 cm

Breadth of tile = 25 cm

Area of tile = $Length \times Breadth = 32 \times 25 = 800 cm^2$

The number of tiles required to cover the wall =$\frac{480000}{800}=600$

Hence 600 tiles are required to cover the wall

#Learn more:

A tile is 15cm long and 10 cmwide . wide.the four walls of the kitchen need to be tiled if the length and breadth of each wall is 440 cm and 750 cm how many tiles will be required to tile the entire kitchen

https://brainly.in/question/2252568