A wallet contains a 20 peso bill, a 50 peso bill, and a 100 peso bill. A bill is taken out from the wallet and then replaced with a bill of the same amount that was taken away. If a bill is taken out from the wallet, what is the probability that the sum of the bills is
70 peso bill
Not 70
More than 40
Use tree diagram to show the sample space:
First Second Outcome(Sum)
Pa help po thanks
Answers
Given : A wallet contains a 20 peso bill, a 50 peso bill, and a 100 peso bill.
A bill is taken out from the wallet and then replaced with a bill of the same amount that was taken away
a bill is taken out from the wallet again
To Find : probability that the sum of the bills is
70 peso bill
Not 70
More than 40
Solution:
20 peso bill, a 50 peso bill, and a 100 peso bill.
3 bills
Total ways of getting bills = 3 x3 = 9
( 20 , 20) , ( 20 , 50) , (20 , 100)
(50 , 20) , ( 50 , 50) , (50 , 100)
(100 , 20 ) , (100 , 50) , (100 , 100)
Find Sum
= (40 , 70 , 120 , 70 , 100 , 150 , 120 , 150 , 200)
Arrange in order
= ( 40 , 70 , 70 , 100 , 120 , 120 , 150 , 150 , 200)
Probability sum of the bills is 70 = 2 / 9
Probability sum of the bills Not 70 = 1 - 2/9 = 7/9
More than 40 = 1 - 40
= 1 - 1/9
= 8/9
20 50 100
↓ ↓ ↓
20 50 100 20 50 100 20 50 100
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