Question

a
WAP a menu deciven program to calculate
Area of rectangle = lxb
Perimeter of rectangle = 2(l+b)
Diagonal of rectangle =
$\sqrt{l^{2} + b ^{2} }$


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Answer 1

$\huge{\underline{\underline{\bf{Python\:(7.3.4))}}}}$

$\huge{\bigstar{\sf{\underline{Coding}\bigstar}}}$

print("1. Calculate area")

print(" 2. Calculate perimeter")

print ("3. Calculate diagonal")

A= int(input("Enter choice:"))

if A=1. :

$\textsf{length= float(input("Enter the length of the rectangle":))}$

$\textsf{breadth=float(input("Enter the breadth of the rectangle))}$

Area= length×breadth

print("Area of rectangle=", end=' '))

while A= 2. :

Perimeter= 2(length + breadth))

print("perimeter of rectangle=",end=' '))

else :

$\textsf{Height=float(input("Enter the height of the rectangle:"))}$

Diagonal= √length**2+breadth**2+height**2

print ("enter diagonal=",end=' '))

$\huge\textsf{Program ends......}$