Math, asked by Steven8206, 11 months ago

A watch gains 10 seconds in 30 minutes and was set right at 1 am. What time will it show at 4 pm on the same day?

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Answered by sankukgp9
0

Answer:

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Answered by ғɪɴɴвαłσℜ
19

Aɴꜱᴡᴇʀ

 \huge \sf 4 \ratio05 \: pm

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Gɪᴠᴇɴ

A watch gains 10 seconds for each 30 minutes and that the

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ᴛᴏ ꜰɪɴᴅ

the time that the watch would show at 4 pm

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Sᴛᴇᴘꜱ

Sonic the watch gains 10 seconds for each 30 minutes then

 \large \sf \leadsto then \: the \: number \:of \: 30 \: minutes \: between \: 1to \: 4 \: are \\  \\ \large \sf the \: number \: of \:30s \: will \: be

There are 60 minutes in an hour and a total of 15 hours between 1 am and 4 pm so then there would be a difference of 15×60 = 900 minutes

So now the number of 30s can be found by

 \large \sf  \leadsto{ \fbox{ \fbox{\large\frac{total \: minutes}{30} }}} \\  \\  \large \sf \leadsto \frac{ \cancel{900}}{ \cancel{30}}  \\  \\  \large \sf \pink{ \leadsto 30 \: times} \\  \\   \large \sf{  \underline{ \underline{}}}

 \large \sf {}so \: then \: the \: gain \: in \: time \: will \: be \\  \\  \large \sf \leadsto30 \times 10 =   \green{300 \: seconds} \\  \\  \large \sf converting \: seconds \: to \: minutes \: and \:adding \: it \: to \: 4pm \\  \\  \large \sf  \leadsto \frac{ \cancel{300}}{ \cancel{60}}  \\  \\  \large \sf { \leadsto}5 \: minutes \\  \\  \large \sf so \: the \: time \: shown \: will \: be \\  \\  \large \sf4  \ratio00 + 5 \: minutes \\  \\  \large \sf \pink{ \leadsto4  \ratio05 \: pm}

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\huge{\mathfrak{\purple{hope\; it \;helps}}}

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