A watch gains time uniformly was observed to be 10 min slow at 6 am on Sunday and it was noticed that the watch was 15 min fast at 8 am on the subsequent Tuesday. When did the watch show the correct time?
Answers
Given : A watch gains time uniformly was observed to be 10 min slow at 6 am on Sunday and it was noticed that the watch was 15 min fast at 8 am on the subsequent Tuesday
To find : When did the watch show the correct time
Solution:
10 min slow at 6 am on Sunday
15 min fast at 8 am on the subsequent Tuesday
Total time = 24 + 24 + 2 = 50 hrs
Watched gained time = 15 - (-10) = 25 minutes
25 minutes gained in 50 hrs
=> 1 Minute gainesd in 50/25 = 2 hrs
=> 10 minute gained in 2 * 10 = 20 hrs
As clock was losing 10 minutes hence gaining 10 minutes would show correct time
=> 6 AM Sunday + 20 hrs
= 2AM Monday
At 2AM Monday watch show correct Time
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