A water heater marked 2kW, 220V is connected to a 220V supply. How long will it take to heat 20kg of water from 10°C to 30°C ?? Assume that all the heat is taken up by the water. ( Specific heat of water = 4200 J kg^-2 C^-2).
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›-» Heat, H = msT
H = m × 4200 × T
H = 20 × 4200 × 20 = 168 × 10⁴ J
Electric energy consumed = power × time
168×10⁴= 2×10³× t
t = 168×10⁴/2×10³
= 840s
= 14min
H = m × 4200 × T
H = 20 × 4200 × 20 = 168 × 10⁴ J
Electric energy consumed = power × time
168×10⁴= 2×10³× t
t = 168×10⁴/2×10³
= 840s
= 14min
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