Question

a water heater produced heat is 3.6 into 10 to the power 3 joule in 10 seconds if the resistance of water heater is 40ohm then find the value of electric current flow in water heater​
please....

Answer 1

Given, heat energy= 3.6×10⁻³J

t= 10s.

So the power of the heater, P= Energy/time

                                                 = (3.6×10⁻³)/ 10

                                                 =3.6×10⁻⁴ Watt

Given, resistance of the heater, R= 40Ω

We know, P= I²R

               I=√(P/R)= √(3.6×10⁻⁴/40)

                              = 3×10⁻³ Amp