Math, asked by shravyaishantdutta12, 8 months ago

A water pipe has an outside diameter of 3.5 cm and a wall thickness of 25/32 cm. What is the inside diameter of the pipe?

Answers

Answered by aarushiwillows
0

Answer:

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Answered by Anonymous
16

Answer:

Inside diameter of the pipe is \sf {1\frac {15}{16}cm }

Step-by-step explanation-

Given,

  • Outside diameter = \sf { 3.5 cm}
  • Wall thickness = \sf { \frac {25}{32}}

To find-

  • Inside diameter of pipe.

Solution-

As outside diameter given= 3.5cm

Radius = \sf { \frac{3.5}{2} cm = 1.75cm}

Inner radius = Outside radius - thickness of pipe

\sf {=> 1.75- \frac {25}{32} }

\sf { =>\frac {175}{100}- \frac {25}{32}= \frac {31}{32} }

\sf {=> \frac {31}{32}} × \sf {2}

( radius to convert into diameter)

\sf {=> \frac {31}{16}= 1\frac {15}{16}cm } Ans..

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