Math, asked by lewiscook7799, 5 hours ago

A water pipe (inner diameter of 15/4 cm and a wall thickness of 5/7cm.What is the outer radius of the pipe

Answers

Answered by garvitgolusingh123
0

Step-by-step explanation:

add 5/7x2 + 15/4 i added multiply by 2 because the thickness will be added from two sides so the new number is

10/7+15/4 now fins lcm and add the the number ia :-

75/28+40/28 115/28 now they said to find the radius so now multiply 1/2*115/28 which is 115/56

answer = 115/56

hope iT helps

Answered by dkchakrabarty01
0

Answer:

Inner radius =15/8

Outer radius=inner radius+thickness

=15/8+5/7=(105+40)/56=145/56cm

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