Math, asked by dayalupawar822, 1 year ago

A water pipe is cut into two pieces. The longer piece is 70% of the length of the pipe. By how much percentage is the longer piece longer than the shorter piece? Choose answer:

Answers

Answered by Anonymous
29
Solutions :-

Given :

A water pipe is cut into two pieces.
The longer piece is 70% of the length of the pipe.

Let the total length of water pipe be 100 m

Therefore,
Length of longer piece = 70% of 100 m
= 70 m

Shorter piece = (100 - 70) m = 30 m


The longer piece longer than the shorter piece = (70 - 30) m = 40 m


Find percent is the longer piece longer than the shorter piece :-

= ( 40 × 100)/30 %
= 4000/30 %
= 133.33 % approx.

Hence,
133.33 % is the longer piece longer than the shorter piece.
Answered by ans81
22
HEY MATE HERE IS YOUR ANSWER

____________________________

Given :-

♕The water pipe is cut into 2 pieces.
♕The longer piece is 70% of the length of the pipe.

____________________________

Solution :-

Let total length of pipe be 100m.

Therefore,

Length of longer piece = 70% of 100 = 70m

Short piece = 100 - 70 = 30m

The longer piece = 70 - 30 = 40m

To find percent of shorter piece :-

 \huge = > \frac{40}{30} \times 100

 \huge = > 133.33\% \: approx
______________________________

Hope it will help you

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