Question

A water pump of power 0.5hp takes 20 sec to lift 100kg of water towards tank. `

Find the height of water to be lifted? (g =10m/s2)​

Answer 1

Given:

A water pump of power 0.5hp takes 20 sec to lift 100kg of water towards tank.

To find:

Height of water to be lifted ?

Calculation:

First of all, let's convert the unit of power from hp to watt :

0.5 hp = 0.5 × 746 = 373 watt.

Now, we know that power is work done per unit time:

$\therefore \: power = \dfrac{work}{time}$

$\implies \: power = \dfrac{mgh}{t}$

$\implies \:343 = \dfrac{100 \times 10 \times h}{20}$

$\implies \:343 = \dfrac{1000 \times h}{20}$

$\implies \:343 = \dfrac{100 \times h}{2}$

$\implies \:50h = 343$

$\implies \: h = 6.86 \: m$

So, height to which water is raised is 6.86 metres.

Answer 2

QUESTION:-

A water pump of power 0.5hp takes 20 sec to lift 100kg of water towards tank.

TO FIND:-

Find the height of water to be lifted

Calculation:-

First of all, let's convert the unit of power from hp to watt :

First of all, let's convert the unit of power from hp to watt :0.5 hp = 0.5 × 746 = 373 watt.

First of all, let's convert the unit of power from hp to watt :0.5 hp = 0.5 × 746 = 373 watt.Now, we know that power is work done per unit time.

We know that

:::::::

$power = \frac{work}{time}$

$= > \: power = \frac{mgh}{t}$

$= = > \: 343 = \frac{100 \times 10 \times h}{20}$

$= > 343 = \frac{1000 \times h}{20}$

$= > \: 343 = \: \frac{100 \times h}{2}$

$= > 50h = 343$

$= > \: h = 6.86 \: m$