Physics, asked by kanikagoel751, 1 year ago

A water pump raises 50 litre of water through a height of 25 m in 5 sec. Calculate the power of the pump required.
(Take g = 10N/kg and density of water =1000 kg/m^3 )

Answers

Answered by afridi7
7
rate of water flow = Q= volume/time = 50/5

Q = 5 ltr/sec

volume = 5 litre = 0.005 m^3

hence mass = vol. × density = 0.005 × 1000

mass = m = 5 kg

potential energy = mgh = 5× 10×25
= 1250 J

hence power = 1250 W




kanikagoel751: The correct answer is 12500 W
afridi7: yes there is mistake sorry , see volume which is 5 litre so correct it to 50litre
afridi7: then after divide 50/5 it will be 10 not 5
afridi7: v= 10 litre = 0.01 m^3
afridi7: sorry ask question again or report my answer so that ican correct it
Answered by Brenquoler
12

Height = 25m

Time = 5s

Volume = 50l

 { \blue{ \bf{  Let's \: convert \: volume \:to \:density: }}}

density = mass / volume

So,

 { \blue{ \bf{  1m² = 1000l }}}

 { \blue{ \bf{ density = mass / volume  }}}

1000=mass/(1/1000×50)

mass=1000×50×1/1000

 { \blue{ \bf{  =50kg }}}

 { \blue{ \bf{W=F=mg=50×10=500   }}}

P=500×25/5

 { \blue{ \bf{P=2500W \: Ans   }}}

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