Physics, asked by dishatomar977, 4 months ago

a water pump takes 20 minutes to pump water to fill a tank of volume 40 metre if the efficiency of pump is 40% and the tank is at the height 15 how electric power is needed for a pump​

Answers

Answered by gurleenkaur143a
2

Explanation:

Here, Volume of water =30 m

3

t=15 min=15×60 s=900 s;Height,h=40 m

Efficiency, η=30%

Density of water =10

3

kg m

−3

∴ Mass of water pumped =Volume×Density

=(30 m

3

)(10

3

kg m

−3

)=3×10

4

kg

P

output

=

t

W

=

t

mgh

=

900 s

(3×10

4

kg)(10 ms

−2

)(40 m)

=

3

4

×10

4

W

Efficiency, η=

P

input

P

output

P

input

=

η

P

output

=

100

30

4×10

4

=

9

4

×10

5

=44.4×10

3

W=44.4 kW.

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
2

Given

  • Volume of tank = 40 m³
  • Density of Water = 10³ kg/m³

To Find

  • Electric Power needed

Solution

● Mass = Volume × Density

● Work Done = Potential Energy = mgh

● Power = Work/Time

Ep = 30% of power needed

Mass of the water pumped :

→ Mass = Volume × Density

→ Mass = 40 × 10³

→ Mass = 4 × 10⁴ kg

Work Done :

→ Work = mgh

→ Work = 4 × 10⁴ × 9.8 × 40

→ Work = 1568 × 10⁴ J

→ Work = 1.568 × 10⁷ J

Power Required :

→ Power = Work/Time

  • Work = 1.568 × 10⁷ J
  • Time = 20 min = 20 × 60 = 1200 sec

→ Power = (1.568 × 10⁷)/1200

→ Power = 13.006 kW

Electric Power Consumed :

→ Electric Power = 30% of power needed to pump

→ Electric Power = 13.066 × 30/100

→ Electric Power = 3.9 kW

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