A water tank can be filled by a ta in 8 hours and emptied by an outlet pipe in 12 hours. How long it will take to fill the cistern if both the tap and the pipe are opened together
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Answered by
9
work done by tap in 1 hour= (1/8) part.
work done by outlet pipe in 1 hour=(1/12) part.
work done by both=(1/8)-(1/12)
=(3-2)/24
=(1/24) part.
therefore,hours required for the tank to be filled=1÷(1/24)
=24 hours.
work done by outlet pipe in 1 hour=(1/12) part.
work done by both=(1/8)-(1/12)
=(3-2)/24
=(1/24) part.
therefore,hours required for the tank to be filled=1÷(1/24)
=24 hours.
Answered by
2
Tank filled in 1 hour = 1/8 th part
tank emptied in one hour = 1/12th part
in 1 hour, effective filling = 1/8 - 1/12 = (3-2)/24 = 1/24 th part
for complete filling, time = 1/(1/24) = 24 hour
tank emptied in one hour = 1/12th part
in 1 hour, effective filling = 1/8 - 1/12 = (3-2)/24 = 1/24 th part
for complete filling, time = 1/(1/24) = 24 hour
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