Math, asked by hamvu, 1 year ago

a water tank has steps inside it . A monkey is sitting on the top first step . The water level is at ninth step. a) he jumps 3 step down and then vack 2 steps up . In how many jumps will he reach the water level ?

Answers

Answered by Anonymous
9
Let the steps moved down be represented by positive integers and the steps moved up be represented by negative integers.

(i) Initially, the monkey was at step = 1

After 1st jump, the monkey will be at step = 1 + 3 = 4

After 2nd jump, the monkey will be at step = 4 + (−2) = 2

After 3rd jump, the monkey will be at step = 2 + 3 = 5

After 4th jump, the monkey will be at step = 5 + (−2) = 3

After 5th jump, the monkey will be at step = 3 + 3 = 6

After 6th jump, the monkey will be at step = 6 + (−2) = 4

After 7th jump, the monkey will be at step = 4 + 3 = 7

After 8th jump, the monkey will be at step = 7 + (−2) = 5

After 9th jump, the monkey will be at step = 5 + 3 = 8

After 10th jump, the monkey will be at step = 8 + (−2) = 6

After 11th jump, the monkey will be at step = 6 + 3 = 9

Clearly, the monkey will be at water level (i.e., 9thstep) after 11 jumps.

Answered by TarunGarg213
9
or

in fist jump he reach = 1+3=4
in second jump = 4-2=2
in third jump = 2+3=5
in fourth jump = 5-2=3
in fifth jump = 3+3=6
in sixth jump = 6-2=4
in seventh jump = 4+3=7
in eight jump = 7-2=5
in nineth jump = 5+3=8
in tenth jump = 8-2=6
in eleventh jump = 6+3=9

so he will reach in 11 steps

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