Question

A water tank of 5000 litres capacity is at 20 m above the ground. It is to be filled within 15
minutes from a tank at ground level by a pump. Calculate power of the pump required in
H.P., if efficiency of pump is 75%.​

Answer 1

Answer:

Depth = d = 20 m

Depth = d = 20 mH = 10 + 20 = 30 m

Depth = d = 20 mH = 10 + 20 = 30 mVolume = V = 2238  l

Depth = d = 20 mH = 10 + 20 = 30 mVolume = V = 2238  lMass of water = m = m=density×volume=1kg/m3×2238m3=2238kg

Depth = d = 20 mH = 10 + 20 = 30 mVolume = V = 2238  lMass of water = m = m=density×volume=1kg/m3×2238m3=2238kgt=PpotentialEnergy=Pmgh=746W2238kg×9.8m/s2×30m=900s=60900min=15min

Step-by-step explanation:

Hope it will helps you

Answer 2

Answer:

Power = P = 1 HP = 746 W

Depth = d = 20 m

H = 10 + 20 = 30 m

Volume = V = 2238 l

Mass of water = m = m=density×volume=1kg/m

3

×2238m

3

=2238kg

t=

P

potentialEnergy

=

P

mgh

=

746W

2238kg×9.8m/s

2

×30m

=900s=

60

900

min=15min