Question

A water tower in New York City has the shape of a cylinder with a cone on top. The cylinder has a diameter of 12 feet and a height of 15 feet. The roof has an inclination angle of 25 degrees.

Answer 1

Missing information :

In this question the diagram is missing.We have the attach the diagram also there is no mention what we have to find .

Given :

inclination angle = 25 degrees.

diameter= 12 feet

$r1\ =\ \frac{diameter}{2}$

$r1\ \ = 6$

height = 15 feet.

To find:

Find the height of the  to the nearest tenth of the foot. 15 ft =?

Volume of the tower to the nearest cubic foot=?

Solution:

Consider that h1 be the height of the cone and r1 is the radius of cylinder

Therefore     $tan25\ degree = \frac{h1}{r1}$

h1=$tan\ 25\ degree \ * \ r1$

$h1=tan\ 25\ degree \ * 6$

h1=2.8 ft

So the height of the  to the nearest tenth =2.8 ft

$V = \pi r^{2} \ h1 + \pi\ r1\ \frac{2h1}{3}$

$V = \pi *\ 36 ( 15 +\ \frac{2.8}{3} )$

$V=\ 1802\ cubic\ foot$

Therefore volume =1802 cubic foot