a waterpipe is cut into 2 pieces. the longer piece is 70% of the length of the pipe. by how much percent is the longer piece longer than the shorter piece
Answers
Answered by
3
Let the water pipe be 100 m.
Then, Length of longer pipe is 70 m.
Length of shorter pipe is 30 m.
Therefore longer pipe is 40 m longer than shorter pipe.
Percentage is 40/30 × 100 = 133.33 %
Then, Length of longer pipe is 70 m.
Length of shorter pipe is 30 m.
Therefore longer pipe is 40 m longer than shorter pipe.
Percentage is 40/30 × 100 = 133.33 %
Answered by
0
Solutions :-
Given :
A water pipe is cut into two pieces.
The longer piece is 70% of the length of the pipe.
Let the total length of water pipe be 100 m
Therefore,
Length of longer piece = 70% of 100 m
= 70 m
Shorter piece = (100 - 70) m = 30 m
The longer piece longer than the shorter piece = (70 - 30) m = 40 m
Find percent is the longer piece longer than the shorter piece :-
= ( 40 × 100)/30 %
= 4000/30 %
= 133.33 % approx.
Hence,
133.33 % is the longer piece longer than the shorter piece.
Given :
A water pipe is cut into two pieces.
The longer piece is 70% of the length of the pipe.
Let the total length of water pipe be 100 m
Therefore,
Length of longer piece = 70% of 100 m
= 70 m
Shorter piece = (100 - 70) m = 30 m
The longer piece longer than the shorter piece = (70 - 30) m = 40 m
Find percent is the longer piece longer than the shorter piece :-
= ( 40 × 100)/30 %
= 4000/30 %
= 133.33 % approx.
Hence,
133.33 % is the longer piece longer than the shorter piece.
Similar questions
Social Sciences,
8 months ago
English,
8 months ago
Math,
8 months ago
Math,
1 year ago
Chemistry,
1 year ago