Question

The factors of (4x^3 + 23x^2 - 41x - 42). plzzz solve it in detail and in steps.

Answer 1

Perform synthetic division.
Possible factors depend on the last number.
Factors of 42 are: 2, 3 and 7.

Let's try x-2:
x=2:
2¦ 4 23. -41. -42
8. 62 -42
---------------------------
4 31. 21. 0. --> 4x^2 +31x +21
Therefore (x-2) is a factor.

Let's try (x+7)
-7¦ 4. 31. 21
-28 -21
--------------------
4. 3. 0. --> 4x + 3 = 0
Therefore (x+7) is another factor.

Lastly, we have 4x + 3 =0. Solving for x, we have x = 3/4.

The factors are: (x-2), (x+7), and (x-3/4).

Answer 2

Answer:

Hope it helps u!!!!!!!!!!!