Physics, asked by chummushrayan, 1 year ago

A wave has a frequency of 3×10^15 sec^-1

The energy of that photon is?

Options:-
A=1.6×10^-12erg
B=3.2×10^-11erg
C=2.0×10^-11erg
D=3.0×10^15erg

Plz answer URGENT.....

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Answers

Answered by 45Gill
67
hllo
here freq. = 3 × 10^15
Energy = h× freq
E = 6.62 × 10^-34 × 3×10^15
E = 19.86 × 10-19J
or
E = 1.98 × 10^-18 ~ 2×10^-18 J
and in erg
E = 2 × 10^-11 erg

so 3rd option is correct , I hope

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Answered by CarliReifsteck
34

Answer:

The energy of that photon is  2\times10^{-11}\ erg.

C is correct option

Explanation:

Given that,

Frequency f = 3\times10^{15}\ sec^{-1}

The energy is the product of the Planck constant and frequency.

In mathematical form,

E = h\times f

Where, E = energy

h = Planck constant

f = frequency

Put the value into the formula

E = 6.62\times10^{-34}\times3\times10^{15}

E=1.986\times10^{-18}

E = 2\times10^{-18}\ J

We know that,

1 J = 10^{7}\ erg

So, The energy in erg is,

E = 2\times10^{-11}\ erg

Hence, The energy of that photon is  2\times10^{-11}\ erg.

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