factorize x^2+4y^2+4y-4xy-2x-8
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Answered by
18
rearranging the terms,
x^2-4xy+4y^2-2x+4y-8
=(x-2y)^2 -2(x-2y) -8
=(x-2y)[(x-2y)-2] -8
=(x-2y)(x-2y-2)-8
hope this helps!
x^2-4xy+4y^2-2x+4y-8
=(x-2y)^2 -2(x-2y) -8
=(x-2y)[(x-2y)-2] -8
=(x-2y)(x-2y-2)-8
hope this helps!
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22
The answer is in the attachment ........
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