A wave of frequency 500 has a velocity of 350m/s ,calculate the distance between two nearest points,90 degree out of phase .
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Answer:
0.7m
Explanation:
since cos90=0, we have
frequency=500Hz [υ]
speed of sound =350m/s[v]
wavelength=?[λ}
w.k.t
v=υλ
350=500λ
λ=0.7m
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