Question

If ABC is an isoceles Triangle right angled at C then prove that ABsquare is equal to 2 AC square.​

Answer 1

${} \huge \underline \red{Correct \: Question - }$

If ABC is an isosceles right triangle right angled at C. Prove that AB^2 = 2AC^2

${} \huge \underline \blue {Solution - }$

Since ∆ABC is right triangle, right angled at C.

Then by Pythagoras theorem

AB^2=AC^2+BC^2

Using BC=AC,we get

AB^2=AC^2+AC^2

Hence, AB^2 = 2AC^2

_______________Proved..

Answer 2

Answer:

By using Pythagoras theorem :

${ab}^{2} = {ac}^{2} + {bc}^{2}$

∆ABC is a isoscele triangle so BC = AC

${ab}^{2} = {ac}^{2} + {ac}^{2} \\ \\ {ab}^{2} = {2ac}^{2}$

Hence proved ✔️