Question

a wave of frequency 500 hz has velocity 360m/sec. the distance between two nearest points 60° out of phase, is

Answer 1

k = speed/frequency


=> k =36/50


now phase difference = (2∏/k )* path difference


60 = (360/36) * 50 * path difference


distance bewtween two nearest points is = path difference = 6/50 metre


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Answer 2

Here the answer...

By this method it can be calculated