Question

A weak acid HX has dissociation constant 10^-5 it form a comman salt NAX on react with alkali the percentage hydrolysis of 0.1 M solution of NAX is

Answer 1

Explanation:

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Answer 2

The percentage hydrolysis of 0.1 M solution of NaX is 0.01%

Explanation:

NaX is a weak acid and strong base salt.

The hydrolysis of NaX is given by the formula:

h = √(Kw/(Ka × C))

Where,

Kw = Equilibrium constant

Ka = Dissociation constant = 10⁻⁵ (given)

C = Concentration = 0.1 M (given)

On substituting the values on the formula, we get,

h = √(10⁻¹⁴/(10⁻⁵ × 0.1))

∴ h = 10⁻⁴

Now, the percentage of hydrolysis is given as:

%h = 10⁻⁴ × 100 = 10⁻²

∴ %h = 0.01%