Among 300 students in a coaching institute, 180 took the Cat exam, 150 took the Xat exam and at least 50 students took neither the Cat nor the Xat. if the number of students who took both the exams is at least N and at most M, find the value of M÷N
Answers
Answered by
0
The value of M÷N is 15/8 = 1.875.
•Let the probability of a student
▪writing the Cat exam by p(A)
▪writing the Xat exam by p(B)
•Given that the number of student who wrote
▪Cat are 180
▪Xat are 150
▪neither Cat nor Xat are atleast 50
•Then the ratio of the maximum to minimum students who wrote Cat and Xat can be computed as follows.
Attachments:
Answered by
0
Value of M÷N is -
- We have been given total number of students = 300
- Students who took CAT - 180
- Students who took XAT - 150
- 50 students took neither exam
- So, P(A U B) = P(A) + P(B) - P(A ∩ B)
- 250 = 150 + 180 - P(A∩B)
- P(A∩B) = 80 (Least number of students who took the exam)
- Most number of students who took exam = 180 = M
- Therefore, M/N = 150/80
- M/N = 15/8
Similar questions