Question

A weak monobune add 12% dissociated in 0.05 M solution, what
percent dissociation in 0 15 X solution.​

Answer 1

Answer:

Dissociation constant of acid K

a

=Cα

2

=0.01×(0.05)

2

=2.5×10

−5

K

a

=Cα

2

2.5×10

−5

=0.05×α

2

α=0.0223

We know that, α=

∧

m

∞

∧

m

c

0.0223=

4×10

−2

∧

m

c

∧

m

c

=8.92×10

−4

ohm

−1

cm

2

mol

−1

Answer 2

Answer in attachment!

Explanation:

• ᴍʀᴋ. ᴛʜᴀɴᴋs ᴀɴᴅ ʙʀᴀɪɴʟɪsᴛ