AB is the diameter of the circle
whose centre is O. AD and BC are perpendiculars
to the line XY. CB meets the circle at E. Prove that
CE = AD.
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Step-by-step explanation:
the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side. OD is parallel to CA and OD is half of CA. Thus, Hence proved.
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