Question

A weather balloon filled with hydrogen ai 1 amt and 27drgee C as volume equal to 1200dm3. On aseending it reaches a place where the temerature is 23drgee C and pressure is 0.5 amt .what is the volume of the balloon at this temperature​

Answer 1

Given: $P_{1} =1atm,T_{1} =27^{o}C ,V_{1} =1200dm^{3} ,P_{2} =0.5atm,T_{2} =23^{o}C$

To find: $V_{2}$

Step-by-step explanation:

Step 1 of 2

The ideal gas equation is PV=nRT.

P is pressure. V is volume. n is number of moles. R is gas constant. T is temperature.

n and R is constant. So,

$\frac{PV}{T} =constant\\\frac{P_{1} V_{1}}{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}$

Step 2 of 2

Substituting the values we will find the volume.

$\frac{1*1200}{300} =\frac{0.5*V_{2}}{296} \\V_{2}=\frac{1*1200*296}{300*0.5} \\V_{2}=2368dm^{3}$

The volume at 23°C is 2368 dm3.