Question

A weight lifter lifts a mass of 250 kg with a
force 5000 N to the height of 5 m.
(a) What is the workdone by the weight
lifter?
(b) What is the workdone by the gravity?
(c) What is the net workdone on the object?​

Answer 1

Answer:

a) Workdone= fd

5000*5=25000

b) 5000*0=0

c) net =5000+0=5000joule

Please mark as brainliest

Answer 2

Answer:

hope..it...helps.....