Question

a weight of 1 kg is suspended from the lower end of a wire of crosssection 10mm^2 find the magnitude and direction of stress produced on it ( g=9.8 ms^_1 ) give relevant and correct answers​

Answer 1

Answer:

980..................................

Answer 2

Divide the given percentages of atoms with their molecular masses

H---4.07/1 =4.07

C---24.27/12 =2.02

Cl--71.65/35.5=2.01

step 2

divide all values with the lowest value obtained.

H---4.07/2.01=2

C---2.02/2.01=1

Cl---2.01/2.01=1

therefore the empirical formula is

CH

2

Cl

WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5

Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C

2

H

4

Cl

2

.