Question

A weight of 20 kg is suspended from a wire the area of cross section of the wire is 1mmsquare and when stretched the length is exactly 6 m when the weight is removed the length reduces to 5.995m calculate the youngs modulus of the material of the wire​

Answer 1

The young's modulus of the wire is Y = 2.39 x 10^11 N/m^2

Explanation:

Given data:

Area of the wire A = 1 mm^2 = 1 ×10−6 m^2  

Δl = 6 m − 5.995 m = 5 × 10^−3 m  

l = 5.995 m

young's modulus of the wire is given as

Y = σ / ε = Mg / πr^2 × l / Δl = Mg / A.Δl

• A = 1 ×10^−3 m^2
• M = 20 kg
• g = 10 m/s^2

Now

Y = 20 x 10 x 5.995 / 1 x 10^-6 x 5 x 10^-3

Y = 1199 / 5 x 10^-9

Y = 239.8 x 10^9 = 2.39 x 10^11 N/m^2

Hence the young's modulus of the wire is Y = 2.39 x 10^11 N/m^2

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A copper wire, bent in the form of a square, encloses an area of 484 cm^2 .

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